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Q.

Weight percent of carbon in methane is ‘X’ and in ethane is ‘Y’. Magnitude of difference between ‘X’ and ‘Y’ is equal to

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a

Zero

b

5

c

6.666

d

7.5

answer is B.

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Detailed Solution

$% of carbon in {CH}_{4} = \frac{12}{16} \times 100 = 75 % (X) % of carbon in C_{2} H_{6} = \frac{24}{30} \times 100 = 80 % (Y)$

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Weight percent of carbon in methane is ‘X’ and in ethane is ‘Y’. Magnitude of difference between ‘X’ and ‘Y’ is equal to