What is the minimum energy required to launch a satellite of mass m from the surface of earth of mass M, radius R in a circular orbit at an altitude 2R

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

\frac{5GmM}{6R}

\frac{5GMm}{R}

$\frac{- GMm}{6R}$

\frac{- GMm}{3R}

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The minimum energy required to launch a satellite at height h = 2R

When it is on surface $T {.E}_{1} = P .E = \frac{- GMm}{R}$

When it is launched at a height = h = 2R

$T {.E}_{2} = \frac{- GMm}{2 (R + h)} = \frac{- GMm}{6 R}$

$Δ T .E = T {.E}_{2} - T {.E}_{1} = \frac{- GMm}{6R} + \frac{GMm}{R} = \frac{5GMm}{6R}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE