What is the volume (in ml) of 0.1 M potassium permanganate solution required to completely oxidise100 ml of 0.5 M ferrous sulphate solution in acidic medium?     

The chemical equation for the titration of ${\text{FeSO}}_4$ with ${\text{KMnO}}_4$ in presence of an acidic medium is follows as below.

$8{\text{H}}_2{\text{SO}}_4+10{\text{FeSO}}_4+2{\text{KMnO}}_4\to 5{\text{Fe}}_2{\left({\text{SO}}_4\right)}_3+{\text{K}}_2{\text{SO}}_4+2{\text{MnSO}}_4+8{\text{H}}_2\text{O}$

For ${\text{KMnO}}_4$ :

${\text{M}}_1=0.1$ ;${\text{V}}_1=?$ and ${\text{n}}_1=2$

For ${\text{FeSO}}_4$ ;

${\text{M}}_2=0.5{\text{M;V}}_2=100{\text{mL and n}}_2=10$

From the following equation,

$\frac{{\text{M}}_1{\text{V}}_1}{{\text{n}}_1}=\frac{{\text{M}}_2{\text{V}}_2}{{\text{n}}_2}$

$\Rightarrow {\text{V}}_1=\frac{{\text{M}}_2{\text{V}}_2}{{\text{n}}_2}\times \frac{n_1}{{\text{M}}_{\text{1}}}$

        $=\frac{\text{0}\text{.5}\times 100}{10}\times \frac{2}{0.1}$

           

$\therefore {\text{V}}_1=100\text{mL}$