What amount is to be repaid on a loan of ₹ 12000 for $1\frac{1}{2}$ years at 10% per annum compounded half yearly?

Principal = ₹ 12000

There are 3 half years in $1\frac{1}{2}$ years.

Therefore, compounding has to be done in 3 times.

Rate of interest = half of 10% = 5% half yearly.

$\mathrm{A}=\mathrm{P}{\left(1+\frac{\mathrm{R}}{100}\right)}^{\mathrm{n}}$

$=₹ 12000{\left(1+\frac{5}{100}\right)}^3$

$=₹ 12000{\left(\frac{21}{20}\right)}^3$

$=₹ 12000\times \frac{21}{20}\times \frac{21}{20}\times \frac{21}{20}$

$=₹ 13891.50$

Therefore, the amount is to be repaid on a loan of ₹ 12000 for $1\frac{1}{2}$ years at 10% per annum compounded half yearly is ₹ 13891.50.