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What approximate volume of 0,40 M $Ba {(OH)}_{2}$ must be added to 50,0 mL of 0.30 M $NaOH$ to get a solution in which the molarity of the ${OH}^{-}$ ions is 0.50 M?

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66 m

133 mL

100 m

33 mL

answer is A.

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Detailed Solution

Suppose, V is the volume required. Then,

$\frac{0 .4 \times V \times 2 + 50 \times 0 .3}{50 + V} = 0 .50$

$V = 33 mL$ .

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