What are the coordinates of the centroid of a triangle if its vertices are X(3, −2), Y(15, 6), and Z(−6, −10)?

Vertices of the triangle XYZ are X(3, −2), Y(15, 6), and Z(−6, −10).
Let G(x, y) be the centroid of the triangle XYZ.
If A(x₁, y₁), B(x₂, y₂) and C(x₃, y₃) are the vertices of a ∆ABC then, the centroid of ∆ABC is given by G(x, y) = $\left(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}\right)$.
∴G(x, y) = $\left(\frac{3+15-6}{3},\frac{-2+6-10}{3}\right)=\left(4,-2\right)$
Thus, the coordinates of the centroid of triangle XYZ are (4, −2).