What are the three consecutive natural numbers such that the sum of the first and second is 15 more than the third?

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12, 13, 14

16, 17, 18

1, 2, 3

23, 24, 25

answer is B.

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Detailed Solution

Let the first number be

x

.
Then as numbers are consecutive,
The second number

= x + 1

.
The third number

= x + 2

.
According to the question,

x + (x + 1) = (x + 2) + 15

Simplifying the above equation, we get,

2 x + 1 = x + 17

2 x − x = 17 − 1

x = 16

.
Putting the value of

x

in the supposed values of the consecutive numbers, we get,
First number

= 16

,
Second number =

16 + 1 = 17

and
Third number =

16 + 2 = 18

.
Thus, the three consecutive natural numbers such that the sum of the first and second is 15 more than the third are 16, 17 and 18.
Hence, option (2) is correct.

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