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Q.

What are the three consecutive natural numbers such that the sum of the first and second is 15 more than the third?


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a

12, 13, 14

b

16, 17, 18

c

1, 2, 3

d

23, 24, 25 

answer is B.

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Detailed Solution

Let the first number be x  .
Then as numbers are consecutive,
The second number =x+1   .
The third number =x+2   .
According to the question,
x+(x+1)=(x+2)+15  
Simplifying the above equation, we get,
2x+1=x+17  
2xx=171  
x=16  .
Putting the value of x   in the supposed values of the consecutive numbers, we get,
First number =16  ,
Second number = 16+1=17   and
Third number = 16+2=18  .
Thus, the three consecutive natural numbers such that the sum of the first and second is 15 more than the third are 16, 17 and 18.
Hence, option (2) is correct.
 

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