What are X and Y in the reaction?
$C_{2} H_{4} + H_{2} {SO}_{4} \overset{80 ° C}{\to} X \overset{H_{2} O / Δ}{\to} Y$

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$C_{2} H_{5} {OSO}_{3} H, C_{2} H_{5} OH$

$C_{2} H_{2} {CH}_{3} CHO$

$C_{2} H_{2}, C_{2} H_{5} SH$

$C_{2} H_{6}, C_{2} H_{5} OH$

answer is C.

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Detailed Solution

Given data : It is given to identify the X and Y $C_{2} H_{4} + H_{2} {SO}_{4} \overset{80 ° C}{\to} X \overset{H_{2} O / Δ}{\to} Y$
Explanation

We need to find X and Y from the above reaction, from the given options.
The complete chemical Reaction is as follows.
$C_{2} H_{4} + H_{2} {SO}_{4} \overset{80 ° C}{⟶} {CH}_{3} {CH}_{2} {HSO}_{4} \underset{H_{2} O}{\overset{Δ}{⟶}} {CH}_{3} {CH}_{2} OH + H_{2} {SO}_{4}$

So the reaction is (Ethylene gas) + (Sulfuric Acid) at 80℃ gives $C H_{3}$ (Methyl), $C H_{2}$ (Methylene), $H_{2} S O_{4}$ (Sulfuric Acid) and we heat evidence with water it gives $C H_{3} C H_{2} O H$ ( Orthopaedically Handicapped).