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Q.

What current is to be passed for 0.25 s for deposition of a certain weight of metal which is equal to its electrochemical equivalent ?

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a

 2 A

b

 4 A   

c

200 A

d

100 A

answer is A.

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Detailed Solution

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From Faraday's laws:

w = \frac{{Eit}}{F}

 

 

Given that  w = Z ( e.c.e )

Z = \frac{{Eit}}{F}

 

 

but we know  Z x F = E

E = Eit \Rightarrow it = 1 \Rightarrow i = \frac{1}{t} = \frac{1}{{0.25}} = 4amp

 

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