What digit can be inserted in the thousands place of the number 92389, so that the number formed is divisible by 11?

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answer is D.

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Detailed Solution

The given numbers are 92389 and 11.
When the difference between the sum of digits present at odd places and sum of digits present at even places is zero or 11 then the number is divisible by 11.
Let required digit be x.
Then number would be 92x389.
Sum of its digits at odd places,
= 9 + 3 + 2
= 14
Sum of its digits at even places,
= 8 + x + 9
= 17 + x
Difference of the two sums,
= 17 + x – 14
= 3 + x
We know that the difference should be 0 or a multiple of 11, then the number is divisible by 11.
If 3 + x = 0
a = - 3
But the number cannot be negative.
Now,
3 + x = 11
x = 11 – 3
x = 8
Hence, 8 can be inserted in the thousands place of the number 92389, so that the number formed is divisible by 11.
Therefore, option 4 is correct.

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