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Q.

What distance should the object be kept in order to obtain an image distance three times the focal length of the diverging mirror?

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a

$u = + 2 f$

b

$u = - 2 f$

c

$u = - 1.5 f$

d

$u = + 1.5 f$

answer is A.

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Detailed Solution

detailed_solution_thumbnail

Using mirror formula spherical mirror $\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

we get $\frac{1}{f} = \frac{1}{u} + \frac{1}{3 f}$

$\begin{array}{l} \frac{- 1}{u} = \frac{1}{f} - \frac{1}{3f} = \frac{2}{3 f} \\ u = \frac{3 f}{2} = - 1.5 f \end{array}$

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