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What distance will it cover in $10 s$ after starting a racing car that has a uniform acceleration of $4 m s^{- 2} ?$

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200 m

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answer is A.

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Detailed Solution

The distance will be

200 m

.
Given:
The initial velocity is

u = 0

Acceleration

a = 4 cm s^{- 2}

Time

t = 10 s

Using the formula;

\Rightarrow s = ut + (\frac{1}{2}) a t^{2}

…..(1) (second equation of motion)
Where

u, s, a,

and

t

are initial velocity, displacement, acceleration and time respectively.
By putting the given values in equation (1), we get,

\Rightarrow s = 0 \times 10 + (\frac{1}{2}) \times 4 \times {(10)}^{2}

\Rightarrow s = 200 m

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