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What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine

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First increases then decrease

Decreases

Increases

None of these

answer is B.

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Detailed Solution

In deep mine $g^{'} = g (1 - \frac{d}{R})$ ; i.e., g decreases so according to $n \propto \sqrt{g},$ frequency also decreases.

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