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What happens when aluminium and zinc salts react with an excess of $NaOH$

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White precipitate is formed

White precipitate of $Al$ redissolves but that of $Zn$ does not

White precipitate of both $Zn$ and $Al$ first formed redissolve in excess of $NaOH$

White precipitate of $Zn$ redissolves and that of $Al$ does not

answer is B.

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Detailed Solution

Zinc salts and aluminium react with $NaOH$ to form a white gelatinous precipitate of $Zn (OH)_{2} and Al (OH)_{3}$ which then redissolve in excess of $NaOH .$

$\begin{aligned} {Zn}^{2 +} + 2 {OH}^{-} \to Zn (OH)_{2} \\ {Al}^{3 +} + 3 {OH}^{-} \to Al (OH)_{3} \end{aligned}$

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