What happens when an aqueous solution of hydrazine reacts with an alkaline solution of copper sulphate?

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N₂ O₃ is formed in the product.

Oxidation state of nitrogen changes from -2 to 0

Dinitrogen is formed in the product.

Cu-oxidation state changes from +2 to 0

answer is A, B, D.

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Detailed Solution

${\overset{- 2}{N}}_{2} H_{4} + 2 \overset{+ 2}{Cu} {SO}_{4} + 4 KOH \to \overset{0}{N_{2}} + 2 \overset{0}{Cu} + 2 K_{2} {SO}_{4} + 4 H_{2} O$

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