What inductance would be needed to store 1.0 kWh of energy in a coil carrying a 200 A current? $(1 \mathrm{kWh}=3.6\times {10}^6\mathrm{J})$

Given energy is 1.0 Kwh
First, we will convert into joules by using the below conversion 1Kwh =$3.6\times {10}^6\mathrm{J}$
So, energy becomes in joules as,
First it will convert into joules by using the below conversion
$1KWh=3.6\times {10}^6\mathrm{J}$
So, energy becomes in joules as
$\begin{array}{l}\mathrm{E}=3.6\times {10}^6\mathrm{J}\\ \mathrm{i}=200\mathrm{A}\\ \mathrm{L}=?\end{array}$
Now we put these value in above formula we get,
$\begin{array}{l}3.6\times {10}^6=\frac{1}{2}\times \mathrm{L}\times (200{)}^2\\ \Rightarrow 7.2\times {10}^6=\mathrm{L}\times 40000\\ \Rightarrow \mathrm{L}=\frac{7200000}{40000}\\ \therefore \mathrm{L}=180\mathrm{H}\end{array}$
The value of inductance needed to store $1.0KWh$ of energy in a coil carrying current a $200\mathrm{A}$ current is $180\mathrm{H}$. The SI unit of inductance is Henry, and it is represented by the symbol H.