What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g = 10 ${\mathrm{ms}}^{-2}$) of an aircraft flying at a speed of 400 ${\mathrm{ms}}^{-1}$ through a circular arc of radius 0.6 km?

Here, v = 400 ${\mathrm{ms}}^{-1}$

          r = 0.6 km = 0.6$\times {10}^3 \mathrm{m}$

         g = 10 ${\mathrm{ms}}^{-2}$

Centripetal acceleration,

    ${\mathrm{a}}_{\mathrm{c}} = \frac{{\mathrm{v}}^2}{\mathrm{r}} = \frac{{(400 {\mathrm{ms}}^{-1})}^2}{0.6 \times {10}^3 \mathrm{m}}$

         = $\frac{16\times {10}^4 {\mathrm{m}}^2{\mathrm{s}}^{-2}}{0.6 \times {10}^3\mathrm{m}} = \frac{16 \times 10}{0.6}{\mathrm{ms}}^{-2}$

        = 26.7 $\times 10 {\mathrm{ms}}^{-2}$

In the units of g ( = 10 ${\mathrm{ms}}^{-2}$), the centripetal acceleration is 26.7