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Q.

What is equivalent capacitance of the combination shown in figure?
$C_{1} = 2 μ F; C_{2} = 4 μ F; C_{3} = 6 μ F$

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a

$12 μ F$

b

$6 μ F$

c

$\frac{12}{11} μ F$

d

$4 μ F$

answer is A.

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Detailed Solution

All the three capacitors $C_{1}, C_{2}, C_{3}$ are connected in parallel $C_{r} = 2 + 4 + 6 = 12 μ F$

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