What is hybridisation of central atom of anionic part of ${PBr}_{5}$ in crystalline state?

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$s p^{2}$

$s p^{3}$

Not applicable

$s p$

answer is D.

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Detailed Solution

The hybridization of ${PBr}_{5}$ is ${sp}^{3} d$ because one electron enters the s orbital, three occupy the p-orbital, and the final electron enters the d-orbitals of the central atom.

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