What is molar solubility of Al(OH)3 in 0.2 M NaOH solution? [Ksp of Al(OH)3 = 2.4 x 10-24]

Al(OH)3⇌Al3+s+3OH−(3s+0.2) Ksp=s(3s+0.2)3 or 2.4×10−24=8×10−3×s ∵s<<<0.2 s=2.4×10−248×10−3=3×10−22

What is molar solubility of Al(OH)3 in 0.2 M NaOH solution? [Ksp of Al(OH)3 = 2.4 x 10-24]

Al(OH)3⇌Al3+s+3OH−(3s+0.2) Ksp=s(3s+0.2)3 or 2.4×10−24=8×10−3×s ∵s<<<0.2 s=2.4×10−248×10−3=3×10−22

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What is molar solubility of Al(OH)₃ in 0.2 M NaOH solution? [K_sp of Al(OH)₃ = 2.4 x 10^-24]

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12 x 10^-23

3 x 10^-22

3 x 10^-19

12 x 10^-21

answer is C.

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Detailed Solution

$Al (OH)_{3} ⇌ \underset{s}{{Al}^{3 +}} + \underset{(3 s + 0 .2)}{3 {OH}^{-}} K_{sp} = s (3 s + 0 .2)^{3} or 2 .4 \times 10^{- 24} = 8 \times 10^{- 3} \times s ∵ s <<< 0 .2 s = [\frac{2 .4 \times 10^{- 24}}{8 \times 10^{- 3}}] = 3 \times 10^{- 22}$