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Q.

What is ratio of Bohr magneton to the nuclear magneton?

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a

$\frac{m_{p}}{m_{e}}$

b

1

c

$\frac{{m_{p}}^{2}}{{m_{e}}^{2}}$

d

$\frac{m_{e}}{m_{p}}$

answer is A.

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Detailed Solution

Bohr magneton $= \frac{eh}{4 {πm}_{e}}$
Nuclear magneton $= \frac{eh}{4 {πm}_{p}}; Ratio = \frac{m_{p}}{m_{e}}$

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