What is ratio of surface energy of 1 small drop and 1 large drop, if 1000 small drops combined to form 1 large drop

Volume of liquid remain same i.e. volume of 1000 small drops will be equal to volume of one big drop

$\begin{array}{l}\mathrm{n}\frac{4}{3}{\mathrm{\pi r}}^3=\frac{4}{3}{\mathrm{\pi R}}^3\Rightarrow 1000{\mathrm{r}}^3={\mathrm{R}}^3\Rightarrow \mathrm{R}=10\mathrm{r}\therefore \frac{\mathrm{r}}{\mathrm{R}}=\frac{1}{10}\\ \frac{\text{ surface energy of one small drop }}{\text{ surface energy of one big drop }}=\frac{4{\mathrm{\pi r}}^2\mathrm{T}}{4{\mathrm{\pi R}}^2\mathrm{T}}=\frac{1}{100}\end{array}$