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Q.

What is standard enthalpy of reaction for the following reaction 12H2g+AgClsAgs+H++Cl given  ΔHfAgCl0=30360calmol1

ΔHf0Cl=40020cal

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a

-8770 cal

b

-9660 cal

c

+8770 cal

d

+9660 cal

answer is B.

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Detailed Solution

ΔHr0=Hp0HR0

=ΔHf(Ag)0+ΔHf0+ΔHf(Cl-)0-12ΔHfH20+ΔHf(AgCl)0={0+0+(-40020)}-12(0)+(-30360)=-9660 cal

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