What is the % of free SO3 in an oleum that is labelled as '104.5%H2SO4′ ?

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What is the % of free SO₃ in an oleum that is labelled as $^{'} 104 .5 % H_{2} {SO}_{4}^{'}$ ?

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answer is 20.

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Detailed Solution

$H_{2} O + {SO}_{3} ⟶ H_{2} {SO}_{4}$
$18 gr of H_{2} O = 80 gr {SO}_{3}$
$4.5 gr of H_{2} O = 20 gr {SO}_{3}$
$∴ 100 gr of oleum continues 20 gr {SO}_{3}$
$(or) 20 % free {SO}_{3}$

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