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What is the additive inverse of each of the following rational numbers: $\frac{4}{9}$ ; $\frac{- 13}{7}$ ; $\frac{5}{- 11}$ ; $\frac{- 11}{- 14}$ ?

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\frac{- 4}{9}; \frac{13}{7}; \frac{5}{11}; \frac{- 13}{14}

\frac{- 4}{9}; \frac{1}{7}; \frac{5}{11}; \frac{- 11}{14}

\frac{- 4}{9}; \frac{13}{7}; \frac{5}{11}; \frac{- 11}{14}

\frac{- 5}{9}; \frac{13}{7}; \frac{5}{11}; \frac{- 11}{14}

answer is C.

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Detailed Solution

The given rational numbers are

\frac{4}{9}

;

\frac{- 13}{7}

;

\frac{5}{- 11}

;

\frac{- 11}{- 14} .

The additive inverse of

\frac{4}{9}

- \frac{4}{9} = \frac{- 4}{9}

.
The additive inverse of

\frac{- 13}{7}

- (\frac{- 13}{7}) = - (- \frac{13}{7}) = \frac{13}{7}

.
We have,

\frac{5}{- 11} = \frac{- 5}{11}

The additive inverse of

\frac{- 5}{11}

- (\frac{- 5}{11})

= - (- \frac{5}{11}) = \frac{5}{11}

.
We have,

\frac{- 11}{- 14} = \frac{11}{14}

The additive inverse of

\frac{11}{14}

- (\frac{11}{14})

= \frac{- 11}{14}

.
Hence, the additive inverse of

\frac{4}{9}

;

\frac{- 13}{7}

;

\frac{5}{- 11}

;

\frac{- 11}{- 14}

\frac{- 4}{9}; \frac{13}{7}; \frac{5}{11}; \frac{- 11}{14}

.
Therefore, option 3 is correct.

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What is the additive inverse of each of the following rational numbers: 49; -137; 5-11; -11-14 ?

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What is the additive inverse of each of the following rational numbers: $\frac{4}{9}$ ; $\frac{- 13}{7}$ ; $\frac{5}{- 11}$ ; $\frac{- 11}{- 14}$ ?