What is the amount of charge possessed by 1 kg of electrons?
Given that mass of an electrons is $9.1 \times 10^{- 31}$ kg.

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$6 .25 \times 10^{10} C$

$1.76 \times 10^{10} C$

$1.76 \times 10^{11} C$

$1.25 \times 10^{10} C$

answer is B.

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Detailed Solution

$\begin{array}{l} n = \frac{M}{m_{e}} = \frac{1 kg}{9 .1 \times 10^{- 31} kg} = 1 .1 \times 10^{30} \\ Therefore, charge on 1 kg of electrons, \\ q = n e = 1 .1 \times 10^{30} \times 1 .6 \times 10^{- 19} = 1 .76 \times 10^{11} C \end{array}$

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