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What is the amount of chlorine evolved when 2 amperes of current is passed for 30 minutes in an aqueous solution of NaCI?

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a

66 g

b

1.32 g

c

33 g

d

99 g

answer is B.

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Detailed Solution

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$\begin{array}{l} At anode {Cl}^{-} \to \frac{1}{2} {Cl}_{2} + e^{-} \\ E_{{Cl}_{2}} = \frac{35 .5 \times 2}{2} = 35 .5 \\ W_{{Cl}_{2}} = \frac{E_{{Cl}_{2}} \times I \times t}{96500} \\ = \frac{35 .5 \times 2 \times 30 \times 60}{96500} = 1 .32 g \end{array}$

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