What is the angular momentum of an electron in Bohr's hydrogen atom whose energy is -0.544 eV?

$\begin{array}{l}\mathrm{By}\mathrm{using}\mathrm{E}=-\frac{13.6}{{\mathrm{n}}^2}\mathrm{eV}\left(\mathrm{for}{\mathrm{H}}_2\mathrm{atom}\right)\\ \Rightarrow -0.544=-\frac{13.6}{{\mathrm{n}}^2}\Rightarrow {\mathrm{n}}^2=25\Rightarrow \mathrm{n}=5\\ \therefore \mathrm{Angular}\mathrm{momentum}=\mathrm{n}\frac{\mathrm{h}}{2\mathrm{\pi }}=\frac{5\mathrm{h}}{2\mathrm{\pi }}.\end{array}$