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What is the angular momentum of an electron in Bohr’s Hydrogen atom whose energy is – 0.544 eV.

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$frac{h}{pi }$

$frac{{2h}}{pi }$

$frac{{5h}}{{2pi }}$

$frac{{7h}}{{2pi }}$

answer is C.

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Detailed Solution

$By,,using,,E = - frac{{13.6}}{{{n^2}}}eV,,,,,,(for,{H_2},atom)$

$Rightarrow - 0.544 = - frac{{13.6}}{{{n^2}}} Rightarrow {n^2} = 25 Rightarrow n = 5$

$therefore Angular,,momentum = nfrac{h}{{2pi }} = frac{{5h}}{{2pi }}$

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