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What is the approximate age of an ancient wooden piece if it is known that the specific activity of C14 nuclide in it amounts to 3/5 of that in fresh trees? Given: the half of C nuclide is 5570 years and $\log_{e}$ (5/3) = 0.5.

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1000 years

2000 years

3000 years

4000 years

answer is D.

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Detailed Solution

Activity of ancient wood $= 3 / 5 x$ activity of lately felled trees $\Rightarrow A = \frac{3}{5} A_{0} = A_{0} e^{- λ t}$
Solve for time t.

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