What is the area of a right-angled triangle when its base is 16 m and height is 6 m?

Given: Base (b) = 16 m, Height (h) = 6 m

We know, the area of a triangle, $\mathrm{A}=\frac{1}{2}\times \mathrm{b}\times \mathrm{h}$.

Substituting the given values in the above formula, we get,

$\mathrm{A}=\frac{1}{2}\times 16\times 6$

$\Rightarrow \mathrm{A}=8\times 6$

$\Rightarrow \mathrm{A}=48 {\mathrm{m}}^2$

Hence, the area of the triangle will be 48 m².