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What is the area of the sector A' OB' if radius of circle is equal to $6$ cm and $∠ AOB = 60 ° ?$

.

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6 πc m^{2}

πc m^{2}

{6 cm}^{2}

(6 + π) c m^{2}

answer is A.

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Detailed Solution

Given, radius of circle is equal to

6

cm and

∠ AOB = 60 °

We know that the area of a sector

= \frac{θ °}{360 °} π r^{2}

\Rightarrow

Area of the sector AOB

= \frac{60 °}{360 °} π (6)^{2}

\Rightarrow

Area of the sector AOB

= 6 πc m^{2}

Hence, the required area is

6 πc m^{2}

.
Hence, option 1 is correct.

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