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What is the change in potential energy ( in calories) of a 10 kg mass after 41.8m of fall?

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2000 cal

1000 cal

800 cal

1500 cal

answer is A.

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Detailed Solution

Change in potential energy = $Δ U = m g h = 10 \times 10 \times 41.8 = 4180 J$
If mechanical energy in joule produces the same temperature change as heat, we write, W=JH, $H = \frac{Δ U}{J} = \frac{4180}{4.18}$ =1000 cal

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