What is the change in the oxidation state of Mn in the reaction of ${\mathrm{MnO}}_4^{-}$ with H₂O₂ in acidic medium?

In acidic medium: 

$3{\mathrm{H}}_2{\mathrm{O}}_2+2{\mathrm{KMnO}}_4\stackrel{ }{\to }2{\mathrm{MnO}}_2+2\mathrm{KOH}+3{\mathrm{O}}_2+2{\mathrm{H}}_2\mathrm{O}$

 The oxidation state of Mn changes from +7 $\stackrel{ }{\to }$ +2.