What is the charge stored on each capacitor $C_{1}and{C}_2$ in the circuit shown in figure?

The current in the circuit is  $I=(12/12)=1A$

Potential across d and c is $12V-3\times 1V=9V$

Capacitance across d and c is $C=\frac{1\times 2}{1+2}=\frac{2}{3}\mu F$

Therefore, charge on either capacitor is $\frac{2}{3}\times 9=6\mu C$