What is the concentration of sugar (${\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}$) in mol ${\mathrm{L}}^{-1}$ if its 20 g are dissolved in enough water to make a final volume up to 2L in

 mol ${\mathrm{L}}^{-1}$?

$\text{ Molar mass of the sugar, }{\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}\text{, }$

$\mathrm{m}=(12\times 12.01)+(22\times 1.0079)+(11\times 16.00)$

$=342.2938 \mathrm{g}{ \mathrm{mol}}^{-1}\approx 342$

$\text{ Given, }w=20 \mathrm{g},V=2 \mathrm{L}$

$\text{ Molarity }=\frac{\mathrm{w}}{\mathrm{m}\times \mathrm{V}\left(\text{ in }\mathrm{L}\right)}$

$=\frac{20}{342\times 2}=0.0292 \mathrm{mol}{ \mathrm{L}}^{-1}$

= 0.0292M