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Q.

What is the condition for the vectors 2i^ + 6j^ - 8k^ and 3i^ - aj^ + bk^ to be parallel?

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a

a=-9/2, b=-6

b

a=4, b=5

c

a=8, b=2

d

a=-9, b=-12

answer is B.

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Detailed Solution

P¯=2i^+6j^8k^,Q=3i^aj^+bk^
For the vectors to be parallel
PxQx=PyQy=PzQz23=6a=8b
On equating 23=6a2a=18a=9
23=8b2b=24b=12

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