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Q.

What is the condition for the vectors 2i+3j4kand3iaj+bk to be parallel

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a

a=6,b=9/2

b

a=4,b=5

c

a=8,b=2

d

a=9/2,b=6

answer is A.

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Detailed Solution

let A=(2i^+3j^4k^)

B=(3i^aj^+bk^)

When these two vectors are parallel, then angle between them is zero.

θ=0

A×B=|A||B|sinθ

(2i^+3j^4k^)×(3i^aj^+bk^)=0

(3b4a)i^(2b+12)j^+(2a9)k^=0

3b=4a

3(6)=4a

2b12=0

2b=12

b=6

3(6)=4a

18=4a

184=a

92=a

b=6

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