What is the correct order of reactivity of alcohols in the following reaction?
$R - OH + HCl \overset{{ZnCl}_{2}}{\to} R - Cl + H_{2} O$

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$2^{\circ} < 1^{\circ} < 3^{\circ}$

$1^{\circ} > 2^{\circ} > 3^{\circ}$

$3^{\circ} > 1^{\circ} > 2^{\circ}$

$3^{\circ} > 2^{\circ} > 1^{\circ}$

answer is C.

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Detailed Solution

$HCl + An \cdot {ZnCl}_{2}$ is known as Lucas reagent. It isused to determine degree of an alcohol.

The reaction follow nucleophilic substitution reaction in which ------OH group is replaced by ------Cl. In this reaction carbocation is formed as intermediate. Higher the stability of intermediate carbocation higher will be the reactivity of reactant molecule. Since 3^∘ carbocation is more stable than 2^∘ carbocation as well as 1^∘ carbocation, so the order of reactivity of alcohols is $3^{\circ} > 2^{\circ} > 1^{\circ} .$

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