What is the correct order of spin only magnetic moment (in BM) of Mn⁺², Cr⁺² and V⁺² ?

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${Mn}^{+ 2} > V^{+ 2} > {Cr}^{+ 2}$

${Mn}^{+ 2} > {Cr}^{+ 2} > V^{+ 2}$

${Cr}^{+ 2} > V^{+ 2} > {Mn}^{+ 2}$

$V^{+ 2} > {Cr}^{+ 2} > {Mn}^{+ 2}$

answer is C.

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Detailed Solution

Spin only magnetic moment depends upon the number of unpaired electrons, more the number of unpaired electrons, greater will be the spin only magnetic moment.

Mn²⁺=1s²2s²2p⁶3s²3p⁶3d⁵4s⁰
Number of unpaired electrons =5

Cr²⁺=1s²2s²2p⁶3s²3p⁶3d⁴4s⁰
Number of unpaired electrons =4

V²⁺=1s²2s²2p⁶3s²3p⁶3d³4s⁰
Number of unpaired electrons =3
So, the correct order of spin only magnetic moment is
Mn²⁺>Cr²⁺>V²⁺