What is the decreasing order of strength of the bases ${OH}^{-}, {NH}_{2}^{-}, H - C \equiv C^{-} and {CH}_{3} - {CH}_{2}^{-}$

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${CH}_{3} - C H_{2}^{-} > N H_{2}^{-} > H - C \equiv C^{-} > {OH}^{-}$

${OH}^{-} < {NH}_{2}^{-} > H - C \equiv C^{-} > {CH}_{3} - {CH}_{2}^{-}$

${NH}_{2}^{-} > H - C \equiv C^{-} > {OH}^{-} > {CH}_{3} - {CH}_{2}^{-}$

$H - C \equiv C^{-} > {CH}_{3} - {CH}_{2}^{-} > {NH}_{2}^{-} > {OH}^{-}$

answer is A.

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Detailed Solution

${CH}_{3} - {CH}_{2}^{-}$ is known as ethyl which is alkene it gives a very weak acid. So, it is a strong base. ${NH}_{2}^{-}$ is also a strong base compared to other which comes from ${NH}_{3}$ a weak acid $H - C \equiv C^{-}$ is known as ethane it gives a strong acid so, it is a weak base and ${OH}^{-}$ is a very weak base which $H_{2} O$ .Decreasing order is ${CH}_{3} - {CH}_{2}^{-} > {NH}_{2}^{-} > H - C \equiv C^{-} > {OH}^{-} .$