What is the decreasing order of the integers 0, 7, – 3, – 9, – 132, 36?

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0 > 7 > – 3 > 36 > –132 > –9

36 > 7 > 0 > –3 > –9 > –132

7 < –3 < 36 < –132 < 0

– 3 >0 > – 132 > 7 > 36

answer is B.

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Detailed Solution

The given numbers are 0, 7, – 3, – 9, – 132, 36.
Decreasing order of the integers means ordering of integers from its highest to lowest value.
Negative integers have the lowest value.
In the case of negative integers, the number with the highest magnitude has the lowest value.
0 lies between all the negative and all the positive integers.
Therefore, the numbers in decreasing order are: 36 > 7 > 0 > – 3 > – 9 > – 132.
The numbers in decreasing order are 36 > 7 > 0 > – 3 > – 9 > – 132.
Hence, the correct option is 2.

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