Q.

What is the degree of dissociation of weak acid HA (C = 0.1 M) in presence of strong acid HB (C = 0.1 M)? Given : Ka=(weak acid )=106

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a

105

b

103

c

106

d

104

answer is A.

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Detailed Solution

HAH++AC00C(1α)                 Weak acid

HBH++B 0.10000.10.1                            strong acid

Now, with the following formula,

Ka=[H]A[HA]106×(HA]=[0.1]A106×C(1α)=[0.1][](1α)1106=(0.1)αα=105

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