What is the density of lead under a pressure of 2 × 108 Nm–2, if the bulk modulus of lead is 8 × 109 Nm–2 and initially density of lead is 11.4 g cm–3 ?

ρ,=ρ1-PB=11.41-2 x 1098 x 1010=11.69 g/cm3

ρ,=ρ1-PB=11.41-2 x 1098 x 1010=11.69 g/cm3

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What is the density of lead under a pressure of 2 × 10⁸Nm^–2, if the bulk modulus of lead is 8 × 10⁹ Nm^–2 and initially density of lead is 11.4 g cm^–3 ?

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11.69 g cm^–3

12.42 g cm^–3

11.89 g cm^–3

12.01 g cm^–3

answer is C.

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$ρ^{,} = \frac{ρ}{1 - \frac{P}{B}} = \frac{11.4}{1 - \frac{2 x 10^{9}}{8 x 10^{10}}} = 11.69 g / {cm}^{3}$

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