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Q.

What is the density of lead under a pressure of 2 × 10⁸Nm^–2, if the bulk modulus of lead is 8 × 10⁹ Nm^–2 and initially density of lead is 11.4 g cm^–3 ?

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a

11.69 g cm^–3

b

12.42 g cm^–3

c

11.89 g cm^–3

d

12.01 g cm^–3

answer is C.

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Detailed Solution

$ρ^{,} = \frac{ρ}{1 - \frac{P}{B}} = \frac{11.4}{1 - \frac{2 x 10^{9}}{8 x 10^{10}}} = 11.69 g / {cm}^{3}$

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