Q.

What is the dimensions of energy in terms' of linear momentum [p], area [A] and time [T]?  

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a

[p1A½T-1]

b

[p½A½T-1]

c

[p1A1T1]

d

[p2A2T-1]

answer is C.

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Detailed Solution

Dimensions of energy in terms of linear momentum (p), area (A) and time (T), is related to
                                           E = paAbyc                                   ... (i)
Writing dimensional formula of both sides, we get
                              [ML2T-2] = [MLT-1]a [L2]b[T]c
                              [ML2T-2] = [MaLa + 2b T-a +c]
Comparing the exponents,
                                         a = 1, a + 2b = 2
                                       2b = 1
                                    b = 12
                          

                                   - a + c = -2
                              -1 + c = -2
                                      c = -l
  From Eq. (i), we have
                             E = [pA½T-1]

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