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Q.

What is the electric flux linked with closed surface?

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a

1011NM2/C

b

1012Nm2/C

c

1010Nm/C

d

8.86×1013Nm2/C

answer is B.

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Detailed Solution

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Electric  flux,  ϕ=qεo

Where q = Total charge enclosed by closed surface

ϕ=1.25+7+10.4εo=8.85C8.85×1012C2N1m2=1012Nm2/C

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