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Q.

What is the electron affinity of iodine(Kcal) based on the following data
a) sublimation energy of  Na=26 Kcal/mole
b) Bond energy of I2=50 Kcal/mole
c) Ionisation enthalpy of Na=118 Kcal/mole
d) Lattice energy of NaI=165 Kcal/mole
e) heat of formation of NaI=69 Kcal/mole 
 

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answer is 73.

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Detailed Solution

Ea=S+D2+IUΔHf 26+25+118-165+69=73 Kcal

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