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What is the energy of the first orbit of ${He}^{+}$ ?

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$- 8.72 \times 10^{- 18} J$

$- 8.72 \times 10^{- 8} J$

$2.18 \times 10^{- 18} J$

$- 4.36 \times 10^{- 8} J$

answer is A.

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Detailed Solution

$E_{n} = \frac{(2.18 \times 10^{- 18} J) Z^{2}}{n^{2}} per a tom$

$En = \frac{(2.18 \times 10^{- 18} J) \times 2^{2}}{{(1)}^{2}} = - 8.72 \times 10^{- 18} J$

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