Q.

What is the energy released in the fission reaction 92236U46117X+46117Y+201n?

It is given that the binding energy per nucleon of X and Y is 8.5 MeV and that of  92236U is 7.6 MeV.

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a

2000 MeV

b

20 MeV

c

180 MeV

d

200 MeV

answer is C.

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Detailed Solution

The energy released is given by:

Q = B.E.products –  B.E.reactants

Q = 8.5(117 + 117) – 7.6(236) = 195.4 MeV  200 MeV

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