What is the expression for the time period of a simple pendulum?

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$T = \frac{1}{2 π} \sqrt{\frac{l}{g}}$

$T = \frac{1}{2 π} \sqrt{\frac{g}{l}}$

$T = \frac{1}{4 π} \sqrt{\frac{l}{g}}$

$T = \frac{1}{4 π} \sqrt{\frac{g}{l}}$

answer is A.

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Detailed Solution

The simple pendulum comprises a small bob of mass ‘m’ suspended by a thin string secured to a platform at its upper end of length (l).

The simple pendulum is a mechanical system that sways or moves in an oscillatory motion. This motion occurs in a vertical plane and is mainly driven by gravitational force.

The time period of a simple pendulum is defined as the time taken by the pendulum to finish one full oscillation and is denoted by “T”. Its expression is given as:

$T = \frac{1}{2 π} \sqrt{\frac{l}{g}}$

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